Re: [Closed REQ 5065]: geomview question: polygons with holes

["Mark Phillips" <mbp>]

> Suppose my 3D object looks like a cube with a hole drilled through it.
> Thus, the top face and bottom faces of this object are indeed a
> polygons with a hole.  Is there any way for me to display my object
> using geomview?

Yes.  You just have to represent the faces containing the hole with
a union of holeless polygons.  E.g. a square with a square hole
could be split into two pieces as follows:


     _________
    |        /|
    |  _____/ |
    | |	    | |
    | |     | |
    | |_____| |
    | /       |
    |/________|


In fact, for this simple example you could actually represent this with
the following single polygon, two of whose edges happen to be the
same edge (the diagonal line).

     _________
    |        /|
    |  _____/ |
    | |	    | |
    | |     | |
    | |_____| |
    |         |
    |_________|


--Mark